1. **State the problem:** An investment of 800 grows by 12% each year. We need to write the equation for this growth and find the value after 10 years. 2. **Formula used:** The formula for compound growth is $$A = P(1 + r)^t$$ where: - $A$ is the amount after time $t$ - $P$ is the initial principal (800 here) - $r$ is the growth rate per period (12% = 0.12) - $t$ is the number of periods (10 years) 3. **Write the equation:** $$A = 800(1 + 0.12)^t = 800(1.12)^t$$ 4. **Calculate the value after 10 years:** $$A = 800(1.12)^{10}$$ 5. **Evaluate:** $$A = 800 \times 3.10585 = 2484.68$$ (rounded to two decimal places) 6. **Interpretation:** After 10 years, the investment will grow to approximately 2484.68.