Subjects finance

Mortgage Payment 2Be239

Step-by-step solutions with LaTeX - clean, fast, and student-friendly.

Use the AI math solver

1. **State the problem:** Calculate the monthly payment for a 30-year mortgage with an equivalent annual rate (EAR) of 4.375% and a loan amount of 220000. 2. **Formula used:** The monthly payment $M$ for a loan amount $P$ with monthly interest rate $r$ and number of payments $n$ is given by: $$M = P \times \frac{r(1+r)^n}{(1+r)^n - 1}$$ 3. **Convert EAR to monthly interest rate:** EAR is given by: $$EAR = (1 + r_{monthly})^{12} - 1$$ Rearranged to find $r_{monthly}$: $$r_{monthly} = (1 + EAR)^{\frac{1}{12}} - 1$$ Given $EAR = 0.04375$, calculate: $$r_{monthly} = (1 + 0.04375)^{\frac{1}{12}} - 1 = 1.04375^{0.083333} - 1$$ Calculate $r_{monthly}$ precisely (do not round early): $$r_{monthly} \approx 0.003569$$ 4. **Calculate number of payments:** $$n = 30 \times 12 = 360$$ 5. **Calculate monthly payment:** $$M = 220000 \times \frac{0.003569(1+0.003569)^{360}}{(1+0.003569)^{360} - 1}$$ Calculate $(1 + r_{monthly})^{360}$: $$1.003569^{360} \approx 3.806$$ Substitute: $$M = 220000 \times \frac{0.003569 \times 3.806}{3.806 - 1} = 220000 \times \frac{0.01358}{2.806}$$ Simplify fraction: $$\frac{0.01358}{2.806} \approx 0.004839$$ Multiply: $$M = 220000 \times 0.004839 = 1064.58$$ 6. **Final answer:** The monthly payment is approximately **1064.58**.