1. **Problem statement:** You want to find the annual income you can withdraw from your retirement savings over 23 years, given your total savings at retirement is $936264.0545 and you expect to live 23 years after retirement. 2. **Formula used:** To find the annual withdrawal amount $P$, we use the annuity payout formula for a present value $PV$ over $n$ years with interest rate $r$: $$PV = P \times \frac{1 - (1 + r)^{-n}}{r}$$ Rearranged to solve for $P$: $$P = PV \times \frac{r}{1 - (1 + r)^{-n}}$$ 3. **Given values:** - $PV = 936264.0545$ - $n = 23$ years - Annual interest rate $r = 0.09$ (9% APR compounded monthly, but for withdrawals yearly, we use annual rate) 4. **Calculate $P$:** $$P = 936264.0545 \times \frac{0.09}{1 - (1 + 0.09)^{-23}}$$ 5. **Calculate denominator:** $$1 - (1 + 0.09)^{-23} = 1 - (1.09)^{-23} = 1 - \frac{1}{(1.09)^{23}}$$ Calculate $(1.09)^{23}$: $$ (1.09)^{23} \approx 7.031$$ So: $$1 - \frac{1}{7.031} = 1 - 0.1422 = 0.8578$$ 6. **Calculate $P$:** $$P = 936264.0545 \times \frac{0.09}{0.8578} = 936264.0545 \times 0.1049 = 98188.5$$ 7. **Interpretation:** You can withdraw approximately $98188.5$ per year for 23 years after retirement. **Final answer:** Your annual income during retirement is approximately **98188.5** per year.