1. **State the problem:** We have a lot with a current revenue of 80000000 that increases by 4% each year. We want to find the revenue for the next year and the second year after that. 2. **Formula used:** The revenue increases by a percentage each year, so we use the formula for compound growth: $$ R_n = R_0 \times (1 + r)^n $$ where $R_n$ is the revenue after $n$ years, $R_0$ is the initial revenue, and $r$ is the growth rate (as a decimal). 3. **Calculate revenue for next year ($n=1$):** $$ R_1 = 80000000 \times (1 + 0.04)^1 = 80000000 \times 1.04 $$ 4. **Calculate revenue for the second year ($n=2$):** $$ R_2 = 80000000 \times (1 + 0.04)^2 = 80000000 \times 1.04^2 $$ 5. **Evaluate the values:** $$ R_1 = 80000000 \times 1.04 = 83200000 $$ $$ R_2 = 80000000 \times 1.0816 = 86528000 $$ 6. **Final answer:** The revenue next year will be **83200000**. The revenue in the second year will be **86528000**.