1. The problem involves understanding the relationship between flow rate and volume. 2. Given flow rate $Q = 11.9$ m³/s and total volume $V = 67205600$ m³, we want to find the time $t$ it takes to accumulate this volume at the given flow rate. 3. The formula relating volume, flow rate, and time is: $$V = Q \times t$$ where $V$ is volume, $Q$ is flow rate, and $t$ is time. 4. To find time, rearrange the formula: $$t = \frac{V}{Q}$$ 5. Substitute the given values: $$t = \frac{67205600}{11.9}$$ 6. Perform the division: $$t = 5647058.82 \text{ seconds}$$ 7. Convert seconds to more understandable units, such as days: $$\text{days} = \frac{t}{86400} = \frac{5647058.82}{86400} \approx 65.36 \text{ days}$$ **Final answer:** It takes approximately **65.36 days** to accumulate 67205600 m³ at a flow rate of 11.9 m³/s.