1. The problem states that Rayen started with $\frac{7}{8}$ kg of flour and after using some, she has $\frac{2}{7}$ kg remaining. We need to find how much flour she used. 2. To find the amount used, subtract the remaining flour from the initial amount: $$\text{Used} = \frac{7}{8} - \frac{2}{7}$$ 3. Find a common denominator to subtract these fractions. The denominators are 8 and 7, so the common denominator is $8 \times 7 = 56$. 4. Convert each fraction: $$\frac{7}{8} = \frac{7 \times 7}{8 \times 7} = \frac{49}{56}$$ $$\frac{2}{7} = \frac{2 \times 8}{7 \times 8} = \frac{16}{56}$$ 5. Subtract the fractions: $$\frac{49}{56} - \frac{16}{56} = \frac{49 - 16}{56} = \frac{33}{56}$$ 6. Simplify if possible. Since 33 and 56 have no common factors other than 1, $\frac{33}{56}$ is in simplest form. 7. To estimate $\frac{33}{56}$, note that $\frac{28}{56} = \frac{1}{2} = 0.5$ and $\frac{33}{56} \approx 0.589$, which is slightly more than $\frac{1}{2}$. 8. Therefore, the amount of flour used is slightly more than half a kilogram. 9. Looking at the graphs, Graph B shows an arrow pointing slightly beyond $\frac{1}{2}$, which matches our calculation. **Final answer:** Rayen used approximately $\frac{33}{56}$ kg of flour, which is slightly more than $\frac{1}{2}$ kg, so Graph B is the reasonable estimate.