1. Calculate the difference $\frac{2}{3} - \frac{1}{5}$ using a grid and counters. Step 1: Find a common denominator for $\frac{2}{3}$ and $\frac{1}{5}$. The denominators are 3 and 5, so the least common denominator (LCD) is 15. Step 2: Convert each fraction to have denominator 15: $$\frac{2}{3} = \frac{2 \times 5}{3 \times 5} = \frac{10}{15}$$ $$\frac{1}{5} = \frac{1 \times 3}{5 \times 3} = \frac{3}{15}$$ Step 3: Subtract the numerators: $$\frac{10}{15} - \frac{3}{15} = \frac{10 - 3}{15} = \frac{7}{15}$$ 2. Calculate the difference $\frac{5}{6} - \frac{1}{4}$ using a grid and counters. Step 1: Find the LCD of 6 and 4, which is 12. Step 2: Convert each fraction: $$\frac{5}{6} = \frac{5 \times 2}{6 \times 2} = \frac{10}{12}$$ $$\frac{1}{4} = \frac{1 \times 3}{4 \times 3} = \frac{3}{12}$$ Step 3: Subtract the numerators: $$\frac{10}{12} - \frac{3}{12} = \frac{10 - 3}{12} = \frac{7}{12}$$ 3. Find the fraction of bloomed flowers that are other flowers. Step 1: Given $\frac{7}{12}$ of flowers have bloomed. Step 2: Of these, $\frac{1}{3}$ are geraniums. Step 3: Calculate the fraction of bloomed flowers that are geraniums: $$\frac{7}{12} \times \frac{1}{3} = \frac{7 \times 1}{12 \times 3} = \frac{7}{36}$$ Step 4: The fraction of bloomed flowers that are other flowers is: $$\frac{7}{12} - \frac{7}{36}$$ Step 5: Find LCD of 12 and 36, which is 36. Step 6: Convert $\frac{7}{12}$ to $\frac{21}{36}$: $$\frac{7}{12} = \frac{7 \times 3}{12 \times 3} = \frac{21}{36}$$ Step 7: Subtract: $$\frac{21}{36} - \frac{7}{36} = \frac{21 - 7}{36} = \frac{14}{36}$$ Step 8: Simplify $\frac{14}{36}$ by dividing numerator and denominator by 2: $$\frac{\cancel{14}^{7}}{\cancel{36}^{18}} = \frac{7}{18}$$ Final answer: The fraction of bloomed flowers that are other flowers is $\frac{7}{18}$.