1. **State the problem:** We have two fruit flies, both heterozygous for body color (Gg), and we want to find the expected offspring phenotypes. 2. **Recall the genetics rule:** Gray body color (G) is dominant over black (g). Heterozygous means genotype Gg. 3. **Set up the Punnett square:** $$\begin{array}{c|cc} & G & g \\ \hline G & GG & Gg \\ g & Gg & gg \\ \end{array}$$ 4. **Determine genotypes and phenotypes:** - GG: gray - Gg: gray - gg: black 5. **Calculate probabilities:** - GG: 1 out of 4 - Gg: 2 out of 4 - gg: 1 out of 4 6. **Calculate phenotype percentages:** - Gray (GG + Gg) = $\frac{1}{4} + \frac{2}{4} = \frac{3}{4} = 75\%$ - Black (gg) = $\frac{1}{4} = 25\%$ 7. **Answer:** The offspring will be 75% gray and 25% black. **Final answer: C. 75% gray, 25% black**