1. **State the problem:** We need to find the expected phenotype frequencies in a lizard population where red belly is recessive and tan belly is dominant. 2. **Recall the Hardy-Weinberg principle:** The genotype frequencies are given by $$p^2 + 2pq + q^2 = 1$$ where: - $$p$$ is the frequency of the dominant allele (tan), - $$q$$ is the frequency of the recessive allele (red). 3. **Given data:** - $$p = 0.35$$ - $$q = 0.65$$ - Genotype frequencies: - $$BB = p^2 = 0.35^2 = 0.12$$ - $$Bb = 2pq = 2 \times 0.35 \times 0.65 = 0.46$$ - $$bb = q^2 = 0.65^2 = 0.42$$ 4. **Phenotype frequencies:** - Since red is recessive, only $$bb$$ genotype shows red phenotype. - Tan phenotype includes both $$BB$$ and $$Bb$$ genotypes. 5. **Calculate phenotype frequencies:** - Red phenotype frequency = $$q^2 = 0.42$$ - Tan phenotype frequency = $$p^2 + 2pq = 0.12 + 0.46 = 0.58$$ 6. **Interpretation:** - Approximately 42% of the population will have red bellies. - Approximately 58% will have tan bellies. **Final answer:** $$\text{Red phenotype frequency} = 0.42 = 42\%$$ $$\text{Tan phenotype frequency} = 0.58 = 58\%$$