Subjects geometry, algebra

Cone Cylinder Volume 268A2A

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1. **Problem:** A cone and a cylinder have the same height and radius. The volume of the cylinder is 162 cm³. Find the volume of the cone. 2. **Formula:** The volume of a cylinder is given by $$V_{cyl} = \pi r^2 h$$ The volume of a cone is given by $$V_{cone} = \frac{1}{3} \pi r^2 h$$ 3. **Key fact:** The volume of a cone is exactly one-third the volume of a cylinder with the same radius and height. 4. **Calculation:** Given $$V_{cyl} = 162$$, then $$V_{cone} = \frac{1}{3} \times 162 = 54$$ 5. **Answer:** The volume of the cone is **54 cm³**. --- 1. **Problem:** Find the value of $$\left(-\frac{7}{4}\right)^2$$. 2. **Formula:** Squaring a fraction means squaring numerator and denominator separately: $$\left(\frac{a}{b}\right)^2 = \frac{a^2}{b^2}$$ 3. **Calculation:** $$\left(-\frac{7}{4}\right)^2 = \frac{(-7)^2}{4^2} = \frac{49}{16}$$ 4. **Answer:** The value is **49/16**. --- Your answers for question 1 (54 cm³) and question 2 (49/16) are correct. **Summary:** - Volume of cone = 54 cm³ - Value of $$\left(-\frac{7}{4}\right)^2 = \frac{49}{16}$$