1. **Problem 1: Find the measure of $\angle G$ in kite KGLF given $KG=30.0$ cm, $GF=54.4$ cm, and $KF=64.0$ cm.\n\n2. Use the Law of Cosines to find $\angle G$ in triangle $KGF$:\n$$c^2 = a^2 + b^2 - 2ab\cos(C)$$\nwhere $c=KF=64.0$, $a=KG=30.0$, $b=GF=54.4$, and $C=\angle G$.\n\n3. Substitute values:\n$$64.0^2 = 30.0^2 + 54.4^2 - 2 \times 30.0 \times 54.4 \times \cos(\angle G)$$\n$$4096 = 900 + 2959.36 - 3264 \cos(\angle G)$$\n\n4. Simplify:\n$$4096 = 3859.36 - 3264 \cos(\angle G)$$\n$$4096 - 3859.36 = -3264 \cos(\angle G)$$\n$$236.64 = -3264 \cos(\angle G)$$\n\n5. Divide both sides by $-3264$:\n$$\cos(\angle G) = \frac{\cancel{236.64}}{\cancel{-3264}} = -0.07247$$\n\n6. Find $\angle G$ by taking the inverse cosine:\n$$\angle G = \cos^{-1}(-0.07247) \approx 94.16^\circ$$\n\n---\n\n7. **Problem 2: Count numbers greater than 17 and not prime between 1 and 30.\n\n8. Prime numbers given: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29. Numbers greater than 17 are 18 to 30.\n\n9. List numbers >17: 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30.\n\n10. Remove primes 19, 23, 29. Remaining: 18, 20, 21, 22, 24, 25, 26, 27, 28, 30. Count = 10.\n\n---\n\n11. **Problem 3: Average rate of change of height $h(t) = -16t^2 + 400$ from $t=1$ to $t=4$.\n\n12. Calculate $h(1)$:\n$$h(1) = -16(1)^2 + 400 = -16 + 400 = 384$$\n\n13. Calculate $h(4)$:\n$$h(4) = -16(4)^2 + 400 = -16(16) + 400 = -256 + 400 = 144$$\n\n14. Average rate of change formula:\n$$\frac{h(4) - h(1)}{4 - 1} = \frac{144 - 384}{3} = \frac{-240}{3} = -80$$\n\n15. The average rate of change is $-80$ feet per second.\n\n**Final answers:**\n- $\angle G \approx 94.16^\circ$ (Choice D)\n- Number of possible outcomes for first clue = 10 (Choice C)\n- Average rate of change = -80 feet per second (Choice B)