1. The problem involves a right triangle with one angle of 45° and the base (askelmitta) length of 65 units. 2. Since one angle is 45° and the triangle is right-angled, the other non-right angle is also 45°, making it an isosceles right triangle. 3. In an isosceles right triangle, the legs are equal in length, and the hypotenuse is $\sqrt{2}$ times the length of each leg. 4. Given the base (one leg) is 65, the hypotenuse $h$ is calculated by the formula: $$h = 65 \times \sqrt{2}$$ 5. Calculate the hypotenuse: $$h = 65 \times 1.4142 = 91.923$$ 6. Therefore, the hypotenuse length is approximately 91.923 units.