1. Stating the problem: We have two adjacent angles \(\angle A\) and \(\angle B\) such that \(\angle B > \angle A\) and their ratio is \(1:14\). We need to find the measures of \(\angle A\) and \(\angle B\).
2. Important rule: Adjacent angles formed by a straight line sum up to 180 degrees. So, \(\angle A + \angle B = 180^\circ\).
3. Let \(\angle A = x\). Then \(\angle B = 14x\) because the ratio is 1:14.
4. Using the sum of adjacent angles:
$$x + 14x = 180$$
$$15x = 180$$
5. Solve for \(x\):
$$x = \frac{180}{15}$$
$$x = 12$$
6. Calculate \(\angle B\):
$$\angle B = 14x = 14 \times 12 = 168$$
7. Final answer:
\(\angle A = 12^\circ\)
\(\angle B = 168^\circ\)
Adjacent Angles 15F40C
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