Subjects geometry

Airplane Distance A229E8

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1. **State the problem:** We need to find the distance from the airplane to the runway, which forms the hypotenuse of a right triangle. 2. **Identify the given values:** The vertical height from the airplane to the runway is $10000$ ft, and the horizontal distance along the runway is $32000$ ft. 3. **Formula used:** Use the Pythagorean theorem for right triangles: $$c = \sqrt{a^2 + b^2}$$ where $c$ is the hypotenuse (distance from airplane to runway), $a$ is the vertical leg, and $b$ is the horizontal leg. 4. **Substitute the values:** $$c = \sqrt{10000^2 + 32000^2}$$ 5. **Calculate the squares:** $$c = \sqrt{100000000 + 1024000000}$$ 6. **Add the values inside the square root:** $$c = \sqrt{1124000000}$$ 7. **Find the square root:** $$c \approx 33527.7$$ 8. **Round to the nearest tenth:** $$c \approx 33527.7 \text{ ft}$$ **Final answer:** The airplane is approximately $33527.7$ ft from the runway.