1. **State the problem:** We are given triangle \(\triangle PQR\) with perimeter 94 units, and \(QS\) bisects \(\angle PQR\). We need to find the lengths \(PS\) and \(RS\).
2. **Recall the Angle Bisector Theorem:** The theorem states that the angle bisector divides the opposite side into segments proportional to the adjacent sides. Mathematically,
$$\frac{PS}{SR} = \frac{PQ}{QR}$$
3. **Identify given values:**
- Perimeter: \(PQ + QR + PR = 94\)
- \(PQ = 22.4\)
- \(QR = 29.2\)
- Let \(PS = x\) and \(RS = y\) so that \(PR = x + y\)
4. **Express perimeter in terms of \(x\) and \(y\):**
$$22.4 + 29.2 + (x + y) = 94$$
Simplify:
$$51.6 + x + y = 94$$
$$x + y = 94 - 51.6 = 42.4$$
5. **Use the Angle Bisector Theorem:**
$$\frac{x}{y} = \frac{22.4}{29.2}$$
6. **Solve for \(x\) in terms of \(y\):**
$$x = y \times \frac{22.4}{29.2}$$
7. **Substitute into the perimeter equation:**
$$x + y = 42.4$$
$$y \times \frac{22.4}{29.2} + y = 42.4$$
8. **Factor out \(y\):**
$$y \left(\frac{22.4}{29.2} + 1\right) = 42.4$$
9. **Calculate the sum inside parentheses:**
$$\frac{22.4}{29.2} + 1 = \frac{22.4 + 29.2}{29.2} = \frac{51.6}{29.2}$$
10. **Solve for \(y\):**
$$y = \frac{42.4 \times 29.2}{51.6}$$
11. **Calculate \(y\):**
$$y = \frac{42.4 \times 29.2}{51.6} = \frac{1238.08}{51.6} \approx 23.98$$
12. **Calculate \(x\):**
$$x = y \times \frac{22.4}{29.2} = 23.98 \times \frac{22.4}{29.2} = 23.98 \times 0.7671 \approx 18.40$$
**Final answer:**
$$PS \approx 18.40 \text{ units}, \quad RS \approx 23.98 \text{ units}$$
Angle Bisector 0B1Da1
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