1. **Stating the problem:** We have a triangle VWY with point X on segment WY. The segment VX is drawn from vertex V to point X on the base WY. 2. **Given information:** The angles \(\angle WVX\) and \(\angle XVY\) are both 19°. 3. **Understanding the terms:** - An **altitude** is a segment from a vertex perpendicular to the opposite side. - An **angle bisector** divides the angle at the vertex into two equal angles. - A **median** connects a vertex to the midpoint of the opposite side. 4. **Analyzing the problem:** Since \(\angle WVX = \angle XVY = 19^\circ\), segment VX divides the angle at V into two equal parts. 5. **Conclusion:** Therefore, \(\overline{VX}\) is an **angle bisector**. **Final answer:** angle bisector