1. **State the problem:** We are given that segment QN bisects angle PQS, meaning it divides angle PQS into two equal angles.
2. **Given:**
- $\angle PQN = (12x + 4)^\circ$
- $\angle NQS = (18x - 14)^\circ$
- Since QN bisects angle PQS, these two angles are equal.
3. **Set up the equation:**
$$12x + 4 = 18x - 14$$
4. **Solve for $x$:**
Subtract $12x$ from both sides:
$$\cancel{12x} + 4 = 18x - 14 - \cancel{12x}$$
$$4 = 6x - 14$$
Add 14 to both sides:
$$4 + 14 = 6x - 14 + 14$$
$$18 = 6x$$
Divide both sides by 6:
$$\frac{18}{\cancel{6}} = \frac{6x}{\cancel{6}}$$
$$3 = x$$
5. **Final answer:**
$$\boxed{3}$$
Thus, the value of $x$ is 3.
Angle Bisector 4A431B
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