1. **Problem statement:** The perimeter of triangle $\triangle PQR$ is 94 units, and $QS$ bisects $\angle PQR$. We need to find the lengths of $PS$ and $RS$.
2. **Relevant theorem:** The Angle Bisector Theorem states that the angle bisector divides the opposite side into segments proportional to the adjacent sides. That is,
$$\frac{PS}{RS} = \frac{PQ}{QR}$$
3. **Given values:**
- Perimeter $P + Q + R = 94$
- $PQ = 22.4$
- $QR = 29.2$
- $PR = PS + RS$ (unknown segments)
4. **Set variables:** Let $PS = x$ and $RS = y$. Then,
$$x + y = PR$$
5. **Find $PR$:** Since perimeter is sum of all sides,
$$PQ + QR + PR = 94$$
$$22.4 + 29.2 + PR = 94$$
$$PR = 94 - 22.4 - 29.2 = 42.4$$
6. **Apply Angle Bisector Theorem:**
$$\frac{x}{y} = \frac{22.4}{29.2}$$
7. **Express $x$ in terms of $y$:**
$$x = y \times \frac{22.4}{29.2}$$
8. **Use $x + y = 42.4$:**
$$y \times \frac{22.4}{29.2} + y = 42.4$$
9. **Factor out $y$:**
$$y \left(\frac{22.4}{29.2} + 1\right) = 42.4$$
10. **Calculate inside parentheses:**
$$\frac{22.4}{29.2} + 1 = \frac{22.4 + 29.2}{29.2} = \frac{51.6}{29.2}$$
11. **Solve for $y$:**
$$y = \frac{42.4 \times 29.2}{51.6}$$
12. **Calculate $y$:**
$$y = \frac{1238.08}{51.6} \approx 23.99$$
13. **Calculate $x$:**
$$x = 23.99 \times \frac{22.4}{29.2} = 23.99 \times 0.7671 \approx 18.41$$
14. **Final answer:**
$$PS \approx 18.41 \text{ units}, \quad RS \approx 23.99 \text{ units}$$
Angle Bisector A6Ebdb
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