1. **Stating the problem:** We are given angles in a circle or polygon with some known and unknown angles labeled as $a$, $b$, $c$, and $d$. The values given are $a=124^\circ$, $b=62^\circ$, and some other angles: $100^\circ$, $136^\circ$, $114^\circ$, $92^\circ$, and $108^\circ$. We need to find the unknown angles $c$ and $d$. 2. **Formula and rules:** The sum of angles around a point is $360^\circ$. Also, in polygons or circles, the sum of angles in certain configurations can be used to find unknown angles. 3. **Using the sum around the center:** Since the dot represents the center, the sum of all angles around it must be $360^\circ$. 4. **Calculate $c$:** From the problem, the angles around the center include $a=124^\circ$, $b=62^\circ$, $100^\circ$, $136^\circ$, and $c^\circ$. We sum the known angles and subtract from $360^\circ$ to find $c$: $$ c = 360 - (124 + 62 + 100 + 136) = 360 - 422 = -62 $$ Since an angle cannot be negative, this suggests $c$ is not part of this sum or the problem context is different. Let's consider the other set of angles for $c$ and $d$. 5. **Calculate $d$:** The other angles given are $114^\circ$, $a=124^\circ$, $92^\circ$, $b=62^\circ$, and $108^\circ$. Assuming these form a polygon or circle around a point, sum them and subtract from $360^\circ$ to find $d$: $$ d = 360 - (114 + 124 + 92 + 62 + 108) = 360 - 500 = -140 $$ Again, negative, so likely $c$ and $d$ are angles inside a polygon where the sum of interior angles applies. 6. **Sum of interior angles of polygon:** For a polygon with $n$ sides, sum of interior angles is $180(n-2)$. If we know the polygon type, we can find $c$ and $d$. 7. **Assuming a quadrilateral with angles $a$, $b$, $c$, $d$:** Sum is $360^\circ$. $$ c + d = 360 - (a + b) = 360 - (124 + 62) = 360 - 186 = 174 $$ Without more info, we cannot find $c$ and $d$ individually. **Final answer:** With given data, $c + d = 174^\circ$ assuming $a$ and $b$ are part of a quadrilateral. If more context is provided, we can solve for $c$ and $d$ individually.