1. **Stating the problem:** We are given that $\angle AOB = 102^\circ$, $\angle DOE$ is 11° larger than $\angle BOC$, and lines AC and BE are straight lines. We need to find $\angle COD$. 2. **Understanding the figure and relationships:** Since AC is a straight line, $\angle AOB + \angle BOC = 180^\circ$ because they form a straight angle at O. 3. **Expressing $\angle BOC$:** From step 2, $\angle BOC = 180^\circ - 102^\circ = 78^\circ$. 4. **Expressing $\angle DOE$:** Given $\angle DOE = \angle BOC + 11^\circ = 78^\circ + 11^\circ = 89^\circ$. 5. **Using the fact that BE is a straight line:** Since BE is straight, $\angle BOC + \angle COD + \angle DOE = 180^\circ$ because these three angles lie on a straight line. 6. **Finding $\angle COD$:** Substitute known values: $$78^\circ + \angle COD + 89^\circ = 180^\circ$$ Simplify: $$\angle COD = 180^\circ - 78^\circ - 89^\circ = 13^\circ$$ **Final answer:** $\angle COD = 13^\circ$.