Subjects geometry

Angle Congruence Ccbb00

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1. **State the problem:** We are given two line segments \(\overline{DE}\) and \(\overline{FG}\) intersecting at point \(H\), where \(H\) is the midpoint of both segments. We know \(\angle 2\) is complementary to \(\angle 3\), and \(\angle 3\) is congruent to \(\angle 4\). We need to prove that \(\angle 2 \cong \angle 4\). 2. **Recall definitions and properties:** - Since \(H\) is the midpoint of both \(\overline{DE}\) and \(\overline{FG}\), the segments \(\overline{DH} \cong \overline{HE}\) and \(\overline{FH} \cong \overline{HG}\). - Complementary angles sum to 90 degrees: \(\angle 2 + \angle 3 = 90^\circ\). - Given \(\angle 3 \cong \angle 4\), so they have equal measures. 3. **Use the given information:** Since \(\angle 2 + \angle 3 = 90^\circ\) and \(\angle 3 = \angle 4\), substitute \(\angle 4\) for \(\angle 3\): $$\angle 2 + \angle 4 = 90^\circ$$ 4. **Analyze the angles:** Because \(\angle 3\) and \(\angle 4\) are congruent and \(\angle 2\) is complementary to \(\angle 3\), \(\angle 2\) must also be complementary to \(\angle 4\). 5. **Prove congruence:** If \(\angle 2 + \angle 4 = 90^\circ\) and \(\angle 3 = \angle 4\), then \(\angle 2\) and \(\angle 4\) are complementary to the same angle \(\angle 3\), implying \(\angle 2 \cong \angle 4\) by the property of congruent complements. **Final answer:** $$\boxed{\angle 2 \cong \angle 4}$$