1. **Problem Statement:** We have a regular hexagon ABEFGH and a regular quadrilateral BCDE sharing the edge BE. We need to find the measure of angle $\angle DEF$.
2. **Key Properties:**
- A regular hexagon has interior angles of $120^\circ$.
- A regular quadrilateral (square) has interior angles of $90^\circ$.
- Since BE is a common side, points B and E are shared.
3. **Analyze the angle $\angle DEF$:**
- Point E is a vertex of both polygons.
- In the quadrilateral BCDE, angle at E is $90^\circ$.
- In the hexagon ABEFGH, angle at E is $120^\circ$.
4. **Determine the angle $\angle DEF$:**
- The angle $\angle DEF$ is formed by points D, E, and F.
- D and C are vertices of the quadrilateral, F is a vertex of the hexagon.
- Since the polygons share edge BE, the angle between edges ED and EF at E is the sum of the interior angles of the two polygons minus $360^\circ$ (full circle) to find the external angle.
5. **Calculate $\angle DEF$:**
- The interior angle at E in the hexagon is $120^\circ$.
- The interior angle at E in the quadrilateral is $90^\circ$.
- The angle between ED and EF is $360^\circ - (120^\circ + 90^\circ) = 360^\circ - 210^\circ = 150^\circ$.
**Final answer:** $\boxed{150^\circ}$
Angle Def 238Be2
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