1. **State the problem:** We need to find the size of the angle marked with the letter $k$ in the triangle.
2. **Identify given angles:** The triangle has an angle of $20^\circ$ at the bottom-left vertex, an exterior angle of $120^\circ$ at the top-right vertex, and the angle $k$ at the bottom-right vertex.
3. **Use the exterior angle theorem:** The exterior angle ($120^\circ$) is equal to the sum of the two opposite interior angles. Let the interior angle at the top-right vertex be $x$. Then,
$$120^\circ = 20^\circ + x$$
4. **Solve for $x$:**
$$x = 120^\circ - 20^\circ = 100^\circ$$
5. **Sum of angles in a triangle:** The sum of interior angles in any triangle is $180^\circ$. So,
$$20^\circ + 100^\circ + k = 180^\circ$$
6. **Solve for $k$:**
$$k = 180^\circ - 20^\circ - 100^\circ = 60^\circ$$
**Final answer:** The size of angle $k$ is $60^\circ$.
Angle K 6B621A
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