Subjects geometry

Angle Msp 8B7E3B

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1. **State the problem:** We need to find the measure of angle $\angle MSP$ given that $\angle MSP = (7x + 60)^\circ$ and $\angle QTR = (108 - 3x)^\circ$. Lines $OQ$ and $PR$ are parallel, and $MN$ is a transversal. 2. **Use the property of parallel lines and transversal:** When two parallel lines are cut by a transversal, alternate interior angles are equal. Here, $\angle MSP$ and $\angle QTR$ are alternate interior angles, so: $$7x + 60 = 108 - 3x$$ 3. **Solve for $x$:** $$7x + 3x = 108 - 60$$ $$10x = 48$$ $$x = \frac{48}{10} = 4.8$$ 4. **Find $\angle MSP$ by substituting $x$ back:** $$\angle MSP = 7(4.8) + 60 = 33.6 + 60 = 93.6^\circ$$ 5. **Conclusion:** The measure of $\angle MSP$ is $93.6^\circ$.