1. **Stating the problem:** We have a person standing 1.5 m from a window of height 90 cm (0.9 m), and a tree 19.5 m from the window with height 7 m. We want to analyze the angles of view formed by lines from the person's eyes to the top and bottom of the window and the tree. 2. **Relevant formula and concept:** The problem involves similar triangles formed by the lines of sight. The angle of view can be related to the tangent of the angle, which is the ratio of the height difference to the horizontal distance. 3. **Convert all measurements to meters:** - Window height: 90 cm = 0.9 m - Person to window distance: 1.5 m - Window to tree distance: 19.5 m - Tree height: 7 m 4. **Calculate the angle of view for the window:** The vertical height is 0.9 m, horizontal distance is 1.5 m. $$\tan(\theta_{window}) = \frac{0.9}{1.5} = 0.6$$ 5. **Calculate the angle of view for the tree:** The vertical height is 7 m, horizontal distance is $1.5 + 19.5 = 21$ m. $$\tan(\theta_{tree}) = \frac{7}{21} = \frac{1}{3} \approx 0.3333$$ 6. **Interpretation:** The person sees the window under a larger angle of view than the tree because the window is closer and smaller, while the tree is taller but farther away. 7. **Summary:** - Angle of view to window top: $\tan^{-1}(0.6) \approx 30.96^\circ$ - Angle of view to tree top: $\tan^{-1}(0.3333) \approx 18.43^\circ$ Thus, the window subtends a larger angle at the person's eye than the tree.