1. The problem asks which angle measure among $w$, $x$, $y$, and $z$ should equal 92° to prove that lines $r$ and $s$ are parallel. 2. When two lines are cut by a transversal, corresponding angles or alternate interior angles must be equal for the lines to be parallel. 3. Given that 92° is marked at the lower intersection, we look for the angle at the upper intersection that corresponds or is alternate interior to this 92° angle. 4. If $w$ is the angle at the upper intersection corresponding to the 92° angle at the lower intersection, then $w$ must equal 92° to prove $r \parallel s$. 5. Therefore, the angle $w$ should equal 92° to prove that $r$ is parallel to $s$. Final answer: $w = 92^\circ$