1. **State the problem:** We are given two triangles with parallel sides BC and DE, and a proportion involving side lengths: $$\frac{16}{?} = \frac{?}{21}$$. We need to find the unknown side lengths represented by "?".
2. **Formula and theorem:** When two lines are parallel in triangles, corresponding sides are proportional. This is the Angle Proportionality Theorem, which states:
$$\frac{AB}{BD} = \frac{AE}{DE} = \frac{AC}{CE}$$
3. **Set variables:** Let the unknown sides be $x$. The proportion is:
$$\frac{16}{x} = \frac{x}{21}$$
4. **Solve the proportion:** Cross-multiply:
$$16 \times 21 = x \times x$$
$$336 = x^2$$
5. **Find $x$:** Take the square root of both sides:
$$x = \sqrt{336}$$
6. **Simplify $\sqrt{336}$:**
$$336 = 16 \times 21$$
$$\sqrt{336} = \sqrt{16 \times 21} = \sqrt{16} \times \sqrt{21} = 4\sqrt{21}$$
7. **Final answer:**
$$x = 4\sqrt{21}$$
This means the unknown side lengths are $4\sqrt{21}$ units.
Angle Proportionality 11A32C
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