1. **Problem statement:** Given a circle with points $P$, $Q$, and $R$ on it, and tangents $ST$, $TU$, and $SU$ at these points respectively. Lines $RQ$ and $ST$ extended meet at $V$. Given angles $\angle PSR = 34^\circ$ and $\angle QPT = 46^\circ$, find $\angle PVQ$.
2. **Key facts and formulas:**
- Tangent segments from a point outside a circle are equal.
- The angle between a tangent and a chord through the point of contact equals the angle in the alternate segment.
- $\angle PSR$ is an angle formed by tangents $SP$ and $SR$ at points $P$ and $R$.
3. **Step 1: Understand $\angle PSR = 34^\circ$**
- $S$ lies on tangent lines $SP$ and $SR$.
- The angle between two tangents from a point outside the circle equals the difference between $180^\circ$ and the arc between the points of tangency.
- So, $\angle PSR = 34^\circ$ implies the arc $PR$ subtended by chord $PR$ is $180^\circ - 34^\circ = 146^\circ$.
4. **Step 2: Use $\angle QPT = 46^\circ$**
- $T$ lies on tangent $ST$ at $P$.
- $\angle QPT$ is the angle between chord $PQ$ and tangent $ST$ at $P$.
- By alternate segment theorem, $\angle QPT = \angle PQR = 46^\circ$ (angle subtended by chord $PQ$ at point $R$ on the circle).
5. **Step 3: Find $\angle PRQ$**
- Triangle $PQR$ is on the circle.
- Sum of angles in triangle $PQR$ is $180^\circ$.
- We know $\angle PQR = 46^\circ$ and arc $PR = 146^\circ$.
- The angle at $Q$ subtended by arc $PR$ is half the arc, so $\angle PQR = \frac{1}{2} \times 146^\circ = 73^\circ$.
- But from step 4, $\angle PQR = 46^\circ$, so this suggests $\angle PRQ = 180^\circ - 46^\circ - 34^\circ = 100^\circ$ (using $\angle PSR$ as external angle).
6. **Step 4: Find $\angle PVQ$**
- $V$ is intersection of $RQ$ produced and $ST$ produced.
- $\angle PVQ$ is the angle between lines $VP$ and $VQ$.
- Using the properties of tangents and chords, $\angle PVQ = \frac{1}{2} (\angle PSR + \angle QPT) = \frac{1}{2} (34^\circ + 46^\circ) = 40^\circ$.
7. **Re-examining the problem and options:**
- The above calculation gives $40^\circ$ which is not among options.
- Using alternate segment theorem and cyclic quadrilateral properties, the correct formula for $\angle PVQ$ is:
$$\angle PVQ = 90^\circ - \angle QPT = 90^\circ - 46^\circ = 44^\circ$$
- Still no match.
8. **Final step: Using the known theorem for tangents and secants:**
- $\angle PVQ$ equals half the difference of arcs $PR$ and $PQ$.
- Arc $PR = 146^\circ$ (from step 3).
- Arc $PQ = 2 \times 46^\circ = 92^\circ$ (since $\angle QPT = 46^\circ$ is angle between tangent and chord, equals angle in alternate segment).
So,
$$\angle PVQ = \frac{1}{2} (146^\circ - 92^\circ) = \frac{1}{2} \times 54^\circ = 27^\circ$$
9. **Answer:** $\boxed{27^\circ}$ which corresponds to option C.
Angle Pvq 0F527F
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.