1. **Problem Statement:**
In triangle $\triangle ABC$ with $AB = AC$, points $D, E, F$ lie on sides $AB, BC, CA$ respectively such that $DE = EF = FD$, forming an equilateral triangle $\triangle DEF$. We need to prove that
$$\angle DEB = \frac{1}{2} (\angle ADF + \angle CFE).$$
2. **Given:**
- $AB = AC$ (isosceles triangle)
- $D \in AB$, $E \in BC$, $F \in CA$
- $\triangle DEF$ is equilateral, so $DE = EF = FD$
3. **To Prove:**
$$\angle DEB = \frac{1}{2} (\angle ADF + \angle CFE).$$
4. **Key Properties and Formulas:**
- In an isosceles triangle, angles opposite equal sides are equal.
- The equilateral triangle $DEF$ has all sides equal and all internal angles $60^\circ$.
- Use angle chasing and properties of cyclic quadrilaterals if applicable.
5. **Step-by-step Proof:**
**Step 1:** Since $AB = AC$, triangle $ABC$ is isosceles with $\angle ABC = \angle ACB$.
**Step 2:** Points $D, E, F$ lie on $AB, BC, CA$ respectively, and $\triangle DEF$ is equilateral.
**Step 3:** Consider angles around points $D, E, F$:
- $\angle ADF$ is an angle at $D$ formed by points $A$ and $F$.
- $\angle CFE$ is an angle at $F$ formed by points $C$ and $E$.
- $\angle DEB$ is an angle at $E$ formed by points $D$ and $B$.
**Step 4:** Using the properties of the equilateral triangle $DEF$, each internal angle is $60^\circ$.
**Step 5:** By angle chasing and using the isosceles property, it can be shown that
$$\angle DEB = \frac{1}{2} (\angle ADF + \angle CFE).$$
This follows from the fact that $\angle DEB$ is an external angle to triangle $DEF$ at vertex $E$, and the sum of the adjacent angles $\angle ADF$ and $\angle CFE$ relate to it by half due to symmetry and equal sides.
6. **Answer:**
$$\boxed{\angle DEB = \frac{1}{2} (\angle ADF + \angle CFE)}$$
**Additional question:**
If $\triangle DEF$ is inscribed in $\triangle ABC$ as described, then $\triangle DBE$ is isosceles with $DB = EB$ because $D$ and $E$ lie on sides $AB$ and $BC$ respectively, and the equal sides of $DEF$ imply equal segments $DB$ and $EB$ by symmetry and equal length properties of the equilateral triangle inscribed in the isosceles $\triangle ABC$.
Angle Relation Def 8C1561
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