1. **State the problem:** We are given angles $m\angle QOS = 53$, $m\angle POR = 56$, and $m\angle POQ = 22$. We need to find $m\angle ROS$.
2. **Understand the setup:** The rays $P$, $Q$, $R$, and $S$ originate from point $O$. The angles are formed between these rays.
3. **Use angle addition:** Since $\angle QOS$ and $\angle POR$ are given, and $\angle POQ$ is between $P$ and $Q$, we can find $\angle ROS$ by considering the full circle around $O$ which sums to $360$ degrees.
4. **Calculate intermediate angles:**
- $\angle QOR = \angle QOS - \angle ROS$ (unknown yet)
- $\angle POR = 56$
- $\angle POQ = 22$
5. **Sum of angles around point $O$:**
$$m\angle POQ + m\angle QOR + m\angle ROS + m\angle POR = 360$$
6. **Express $m\angle QOR$ in terms of known angles:**
Since $m\angle QOS = 53$, and $m\angle ROS$ is what we want, then
$$m\angle QOR = m\angle QOS - m\angle ROS = 53 - m\angle ROS$$
7. **Substitute into the sum:**
$$22 + (53 - m\angle ROS) + m\angle ROS + 56 = 360$$
8. **Simplify:**
$$22 + 53 - m\angle ROS + m\angle ROS + 56 = 360$$
$$22 + 53 + 56 = 360$$
$$131 = 360$$
This is a contradiction, so let's reconsider the angle relationships.
9. **Re-examine the problem:** The rays are arranged as $P$, $Q$, $R$, $S$ counterclockwise. The angles given are:
- $m\angle QOS = 53$ (between $Q$ and $S$)
- $m\angle POR = 56$ (between $P$ and $R$)
- $m\angle POQ = 22$ (between $P$ and $Q$)
We want $m\angle ROS$ (between $R$ and $S$).
10. **Sum of angles around $O$:**
$$m\angle POQ + m\angle QOR + m\angle ROS + m\angle SOP = 360$$
Note $m\angle SOP = m\angle QOS + m\angle ROS$ because $S$ is between $Q$ and $P$.
11. **Calculate $m\angle QOR$:**
Since $m\angle POR = 56$ and $m\angle POQ = 22$, then
$$m\angle QOR = m\angle POR - m\angle POQ = 56 - 22 = 34$$
12. **Calculate $m\angle ROS$:**
Since $m\angle QOS = 53$, and $m\angle QOS = m\angle QOR + m\angle ROS$, then
$$53 = 34 + m\angle ROS$$
$$m\angle ROS = 53 - 34 = 19$$
**Final answer:**
$$\boxed{19}$$
Angle Ros A597Da
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