1. **State the problem:** We need to find the measure of angle $\angle RTN$ given two expressions for angles formed by two parallel lines cut by a transversal: one angle is $(55 - 2x)^\circ$ and another is $(63 - 6x)^\circ$.
2. **Identify the relationship:** Since the lines are parallel and cut by a transversal, corresponding angles or alternate interior angles are equal. The angles at points $S$ and $R$ are related by this property.
3. **Set up the equation:** Because the angles at $S$ and $R$ are alternate interior angles, they are equal:
$$55 - 2x = 63 - 6x$$
4. **Solve for $x$:**
$$55 - 2x = 63 - 6x$$
$$55 - 2x + 6x = 63$$
$$55 + 4x = 63$$
$$4x = 63 - 55$$
$$4x = 8$$
$$x = \frac{8}{4}$$
$$x = 2$$
5. **Find $\angle RTN$:** The angle $\angle RTN$ corresponds to the angle at $R$, which is $(63 - 6x)^\circ$.
Substitute $x=2$:
$$\angle RTN = 63 - 6(2) = 63 - 12 = 51^\circ$$
6. **Final answer:**
$$\boxed{51^\circ}$$
Angle Rtn 9B3Fb0
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