1. **State the problem:** We need to find the size of angle $t$ in a triangle formed by two parallel lines intersected by a transversal, where two angles are given: $123^\circ$ and $109^\circ$, and the triangle is isosceles with two equal sides.
2. **Identify key facts and formulas:**
- The sum of angles in any triangle is $180^\circ$.
- Alternate interior angles formed by a transversal with parallel lines are equal.
- In an isosceles triangle, the two angles opposite the equal sides are equal.
3. **Analyze the given angles:**
- The $123^\circ$ angle is on the left side, outside the triangle.
- The $109^\circ$ angle is on the top right corner, outside the triangle.
- The pink angle $t$ is inside the triangle.
4. **Find the third angle of the triangle:**
Since the triangle is isosceles with two equal sides, the two base angles are equal. Let these equal angles be $t$ and $t$.
5. **Use the fact that the sum of angles on a straight line is $180^\circ$:**
- The angle adjacent to $123^\circ$ inside the triangle is $180^\circ - 123^\circ = 57^\circ$.
- The angle adjacent to $109^\circ$ inside the triangle is $180^\circ - 109^\circ = 71^\circ$.
6. **Since the triangle is isosceles, the two equal angles are $t$ and $t$, and the third angle is either $57^\circ$ or $71^\circ$. We check which matches the isosceles property.**
7. **Sum of angles in triangle:**
$$ t + t + 57 = 180 $$
$$ 2t = 180 - 57 $$
$$ 2t = 123 $$
$$ t = \frac{123}{2} = 61.5^\circ $$
8. **Check with the other angle:**
$$ t + t + 71 = 180 $$
$$ 2t = 109 $$
$$ t = 54.5^\circ $$
Since the triangle is isosceles, the two equal angles must be the same. The only consistent value is $t = 61.5^\circ$ when the third angle is $57^\circ$.
**Final answer:**
$$ t = 61.5^\circ $$
Angle T 1D54A2
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