1. **Problem:** Find $m\angle V$ in the parallelogram where angles are given as $36x - 1$ and $29x + 1$, with $x=2$ and another angle $50^\circ$. 2. **Formula and rules:** In a parallelogram, opposite angles are equal and adjacent angles are supplementary (sum to $180^\circ$). 3. **Calculate $m\angle V$:** $$m\angle V = 36x - 1$$ Substitute $x=2$: $$m\angle V = 36(2) - 1 = 72 - 1 = 71^\circ$$ 4. **Check with adjacent angle:** Adjacent angle is $50^\circ$, sum should be $180^\circ$: $$71^\circ + 50^\circ = 121^\circ \neq 180^\circ$$ This suggests $29x + 1$ is the other angle adjacent to $50^\circ$. Calculate $29x + 1$ with $x=2$: $$29(2) + 1 = 58 + 1 = 59^\circ$$ Sum with $50^\circ$: $$59^\circ + 50^\circ = 109^\circ \neq 180^\circ$$ Since the problem states $x=2$, we take $m\angle V = 71^\circ$ as the answer. **Final answer:** $$m\angle V = 71^\circ$$