1. The problem asks to find the value of angle $x$ in the first figure (top-left) where two parallel horizontal lines are intersected by a diagonal transversal.
2. The given angle is $131^\circ$ below the top line, and $x$ is above the bottom line on the transversal.
3. According to the rule of alternate interior angles, when two parallel lines are cut by a transversal, alternate interior angles are equal.
4. Therefore, $x = 131^\circ$ because $x$ and $131^\circ$ are alternate interior angles.
5. This means the measure of angle $x$ is $131^\circ$.
Final answer: $x = 131^\circ$
Angle X 3A6B31
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