1. **State the problem:** We have a triangle with vertices C, M, N, and B, where segment MN is parallel to side CB. Given angles at M are 35° and 60°, and we need to find the angle $x$ at vertex C adjacent to side CM. 2. **Recall the rule:** When a segment is drawn parallel to one side of a triangle, corresponding angles are equal due to alternate interior angles. 3. **Apply the rule:** Since MN is parallel to CB, the angle at C adjacent to CM, which is $x$, corresponds to the angle at M between the top segment and side CM, which is 35°. 4. **Conclusion:** Therefore, $x = 35^\circ$. Final answer: $$x = 35^\circ$$