Question: A line labeled as $E D$. A is the point between $E$ and $D$. Three angles made by the 2 rays that is $A B$ and $A C$ are divided it into unequal parts. The measurements of these unequal angles that is $E A B$, $B A C$, $C A D$ are $100$ degrees, $x$ degrees and $20$ degrees respectively.
$x = $
$\Large{{}^\circ}$
1. **State the problem:** We have a straight line $E D$ with point $A$ between $E$ and $D$. Rays $A B$ and $A C$ create three angles: $E A B = 100^\circ$, $B A C = x^\circ$, and $C A D = 20^\circ$. We need to find $x$.
2. **Recall the rule:** The sum of angles on a straight line is $180^\circ$.
3. **Set up the equation:**
$$E A B + B A C + C A D = 180^\circ$$
4. **Substitute known values:**
$$100 + x + 20 = 180$$
5. **Simplify:**
$$120 + x = 180$$
6. **Isolate $x$:**
$$x = 180 - 120$$
7. **Calculate:**
$$x = 60$$
**Final answer:**
$$\boxed{60^\circ}$$