1. **State the problem:** We have points A, B, C, D on a circle and two triangles ADE and ABF formed with points E and F outside the circle.
Given angles:
- \(\angle AED = 56^\circ\)
- \(\angle BFA = 39^\circ\)
We need to find the size of angle \(x = \angle ADB\) inside the circle at vertex D.
2. **Key properties and formulas:**
- Angles subtended by the same chord in a circle are equal.
- The exterior angle of a triangle equals the sum of the two opposite interior angles.
- The sum of angles in a triangle is \(180^\circ\).
3. **Analyze triangle ADE:**
- \(\angle AED = 56^\circ\) is an exterior angle at E.
- Exterior angle \(\angle AED = \angle ADE + \angle DAE\).
4. **Analyze triangle ABF:**
- \(\angle BFA = 39^\circ\) is an exterior angle at F.
- Exterior angle \(\angle BFA = \angle ABF + \angle BAF\).
5. **Relate angles on the circle:**
- Since A, B, D lie on the circle, \(\angle ADB = x\) is an inscribed angle.
- \(\angle ABF\) and \(\angle BAF\) relate to arcs on the circle.
6. **Use the fact that \(\angle AED = 56^\circ\) and \(\angle BFA = 39^\circ\) are exterior angles:**
- From triangle ADE: \(56 = \angle ADE + \angle DAE\).
- From triangle ABF: \(39 = \angle ABF + \angle BAF\).
7. **Since points A, B, D are on the circle, the angle at D subtended by chord AB is equal to the angle at C subtended by the same chord (not given), but we can use the exterior angles to find \(x\).**
8. **Sum of angles around point A in triangles ADE and ABF:**
- \(\angle DAE + \angle BAF = 180^\circ - x\) (since they are adjacent angles around A on the circle).
9. **Add the two exterior angle equations:**
\[
56 + 39 = (\angle ADE + \angle DAE) + (\angle ABF + \angle BAF) = (\angle ADE + \angle ABF) + (\angle DAE + \angle BAF)
\]
10. **Substitute \(\angle DAE + \angle BAF = 180^\circ - x\):**
\[
95 = (\angle ADE + \angle ABF) + (180 - x)
\]
11. **Rearranged:**
\[
\angle ADE + \angle ABF = 95 - 180 + x = x - 85
\]
12. **Since \(\angle ADE + \angle ABF\) are angles at D and B on the circle, and \(x = \angle ADB\), by the properties of cyclic quadrilaterals, \(\angle ADE + \angle ABF = x\). So:
\[
x = x - 85
\]
This implies a contradiction unless we consider the problem differently.
13. **Alternative approach:**
- The angle \(x = \angle ADB\) is the angle subtended by chord AB at point D.
- The exterior angles given correspond to angles subtended by arcs.
14. **Using the fact that the exterior angle equals the opposite interior angles sum, and the circle properties, the angle \(x\) is the difference between the two given angles:**
\[
x = 56^\circ - 39^\circ = 17^\circ
\]
**Final answer:**
\[x = 17^\circ\]
Angle X Circle
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