1. **State the problem:** We need to find the measure of angle $Y$ in triangle $XYZ$ where the sides are $XY=12$, $XZ=15$, and $YZ=20$.
2. **Formula used:** Use the Law of Cosines to find angle $Y$. The Law of Cosines states:
$$\cos Y = \frac{XY^2 + YZ^2 - XZ^2}{2 \cdot XY \cdot YZ}$$
3. **Substitute the known values:**
$$\cos Y = \frac{12^2 + 20^2 - 15^2}{2 \cdot 12 \cdot 20} = \frac{144 + 400 - 225}{480} = \frac{319}{480}$$
4. **Calculate the cosine value:**
$$\cos Y = 0.6645833...$$
5. **Find angle $Y$ by taking the inverse cosine:**
$$Y = \cos^{-1}(0.6645833)$$
6. **Calculate the angle in degrees:**
$$Y \approx 48.3^\circ$$
**Final answer:**
$$m\angle Y \approx 48.3^\circ$$
Angle Y C09012
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