1. **State the problem:** We need to find the length of the arc AB of a sector of a circle with radius 43 mm and central angle 62°. 2. **Formula for arc length:** The length of an arc $s$ is given by the formula: $$s = r \theta$$ where $r$ is the radius and $\theta$ is the central angle in radians. 3. **Convert angle to radians:** Since the angle is given in degrees, convert it to radians using: $$\theta = 62^\circ \times \frac{\pi}{180^\circ} = \frac{62\pi}{180} = \frac{31\pi}{90}$$ 4. **Calculate arc length:** Substitute $r = 43$ mm and $\theta = \frac{31\pi}{90}$ into the formula: $$s = 43 \times \frac{31\pi}{90} = \frac{43 \times 31 \pi}{90} = \frac{1333 \pi}{90}$$ 5. **Evaluate the numerical value:** Using $\pi \approx 3.1416$, $$s \approx \frac{1333 \times 3.1416}{90} = \frac{4187.5}{90} \approx 46.5 \text{ mm}$$ 6. **Final answer:** The length of the arc AB is approximately **46.5 mm** to 1 decimal place.