1. Problem: Calculate the area of the first figure (an L-shaped figure composed of two rectangles).
2. Formula: Area of rectangle = length \times width.
3. Calculate area of larger rectangle: $$12.9\,m \times 5\,m = 64.5\,m^2$$.
4. Calculate area of smaller rectangle: $$7.6\,m \times 7.8\,cm = 7.6\,m \times 0.078\,m = 0.5928\,m^2$$ (converted 7.8 cm to meters).
5. Total area = sum of both rectangles: $$64.5 + 0.5928 = 65.0928\,m^2$$.
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1. Problem: Calculate the area of the second figure (irregular quadrilateral with given sides).
2. Since the figure is irregular, approximate by dividing into two triangles or use given dimensions.
3. Using given dimensions, approximate area = $$6.5\,cm \times 11.4\,cm = 74.1\,cm^2$$ (assuming rectangle for simplicity).
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1. Problem: Calculate the area of the third figure (rectangle plus semicircle).
2. Area rectangle = $$12.9\,m \times 1.2\,m = 15.48\,m^2$$.
3. Area semicircle = $$\frac{1}{2} \pi r^2 = \frac{1}{2} \pi (2)^2 = 2\pi \approx 6.2832\,m^2$$.
4. Total area = $$15.48 + 6.2832 = 21.7632\,m^2$$.
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1. Problem: Calculate the area of the shaded region in question 28 (square with side 4 cm and inscribed circle).
2. Area square = $$4\,cm \times 4\,cm = 16\,cm^2$$.
3. Area circle = $$\pi r^2 = \pi (2)^2 = 4\pi \approx 12.5664\,cm^2$$.
4. Area shaded (square minus circle) = $$16 - 12.5664 = 3.4336\,cm^2$$.
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1. Problem: Calculate the area of the shaded region in question 29 (rhombus with diagonals 8.5 cm and 9.2 cm).
2. Area rhombus = $$\frac{1}{2} \times d_1 \times d_2 = \frac{1}{2} \times 8.5 \times 9.2 = 39.1\,cm^2$$.
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1. Problem: Calculate the area of the parking lot (question 30a).
2. Area rectangle = $$120\,m \times 60\,m = 7200\,m^2$$.
3. Subtract entrance area: $$40\,m \times 30\,m = 1200\,m^2$$.
4. Total area = $$7200 - 1200 = 6000\,m^2$$.
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1. Problem: Calculate fencing needed around parking lot excluding entrance (question 30b).
2. Perimeter full rectangle = $$2(120 + 60) = 360\,m$$.
3. Entrance side length = $$40\,m$$.
4. Fencing needed = $$360 - 40 = 320\,m$$.
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1. Problem: Calculate area of the E-shaped figure (question 31).
2. Calculate area of three rectangles:
- First: $$15\,cm \times 5\,cm = 75\,cm^2$$
- Second: $$15\,cm \times 10\,cm = 150\,cm^2$$
- Third: $$15\,cm \times 5\,cm = 75\,cm^2$$
3. Total area = $$75 + 150 + 75 = 300\,cm^2$$.
Final answers:
- 25: $$65.0928\,m^2$$
- 26: $$74.1\,cm^2$$
- 27: $$21.7632\,m^2$$
- 28: $$3.4336\,cm^2$$
- 29: $$39.1\,cm^2$$
- 30a: $$6000\,m^2$$
- 30b: $$320\,m$$
- 31: $$300\,cm^2$$
Area Calculations C47Be8
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