1. **State the problem:** We need to determine which figure has a greater area: a rectangle with length 16 mm and width 8 mm, or a parallelogram with base 13 mm and height 12 mm. 2. **Formulas:** - Area of a rectangle: $$\text{Area} = \text{length} \times \text{width}$$ - Area of a parallelogram: $$\text{Area} = \text{base} \times \text{height}$$ 3. **Calculate the area of the rectangle:** $$\text{Area}_{rectangle} = 16 \times 8 = 128 \text{ mm}^2$$ 4. **Calculate the area of the parallelogram:** $$\text{Area}_{parallelogram} = 13 \times 12 = 156 \text{ mm}^2$$ 5. **Compare the areas:** - Rectangle area = 128 mm² - Parallelogram area = 156 mm² Since $$156 > 128$$, the parallelogram has the greater area. **Final answer:** The parallelogram has a greater area than the rectangle.