1. **State the problem:** Find the area of a composite figure made of a parallelogram and a semicircle. 2. **Identify given dimensions:** - Parallelogram base $b = 10$ units - Parallelogram height $h = 6$ units - Semicircle diameter $d = 8$ units 3. **Formula for area of parallelogram:** $$\text{Area}_{\text{parallelogram}} = b \times h$$ 4. **Calculate area of parallelogram:** $$10 \times 6 = 60$$ 5. **Formula for area of a circle:** $$\text{Area}_{\text{circle}} = \pi r^2$$ 6. **Calculate radius of semicircle:** $$r = \frac{d}{2} = \frac{8}{2} = 4$$ 7. **Calculate area of semicircle:** $$\text{Area}_{\text{semicircle}} = \frac{1}{2} \pi r^2 = \frac{1}{2} \pi (4)^2 = \frac{1}{2} \pi 16 = 8\pi$$ 8. **Calculate total area:** $$\text{Area}_{\text{total}} = 60 + 8\pi$$ 9. **Approximate using $\pi \approx 3.1416$:** $$8 \times 3.1416 = 25.1328$$ $$60 + 25.1328 = 85.1328$$ 10. **Round to nearest tenth:** $$85.1$$ **Final answer:** The area of the figure is approximately $85.1$ square units.