1. **State the problem:** We need to find the areas of Rectangle A, Rectangle B, and Triangle C, then find the total area of the composite figure. 2. **Formulas used:** - Area of a rectangle = length \times width - Area of a triangle = \frac{1}{2} \times base \times height 3. **Calculate area of Rectangle A:** Given length = 6 ft, width = 4 ft $$\text{Area}_A = 6 \times 4 = 24 \text{ square feet}$$ 4. **Calculate area of Rectangle B:** Given length = 8 ft, width = 2 ft $$\text{Area}_B = 8 \times 2 = 16 \text{ square feet}$$ 5. **Calculate area of Triangle C:** Given base = 4 ft, height = 4 ft $$\text{Area}_C = \frac{1}{2} \times 4 \times 4 = \frac{1}{2} \times 16 = 8 \text{ square feet}$$ 6. **Calculate total area of the figure:** $$\text{Total Area} = \text{Area}_A + \text{Area}_B + \text{Area}_C = 24 + 16 + 8 = 48 \text{ square feet}$$ **Final answers:** - Rectangle A: 24 square feet - Rectangle B: 16 square feet - Triangle C: 8 square feet - Total area of the figure: 48 square feet