1. **Problem Statement:** Find the area of the given compound figure composed of rectangles and triangles with the given side lengths in yards. 2. **Step 1: Understand the figure and divide it into simpler shapes.** The figure can be divided into a rectangle and two right triangles. 3. **Step 2: Calculate the area of the rectangle.** The rectangle has a height of 9 yd and a width of 4 yd. $$\text{Area}_{rectangle} = \text{height} \times \text{width} = 9 \times 4 = 36$$ 4. **Step 3: Calculate the area of the top right triangle.** The triangle has a base of 1 yd and a height of 2 yd. $$\text{Area}_{triangle1} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 1 \times 2 = 1$$ 5. **Step 4: Calculate the area of the bottom right triangle.** The triangle has a base of 1 yd and a height of 3 yd. $$\text{Area}_{triangle2} = \frac{1}{2} \times 1 \times 3 = 1.5$$ 6. **Step 5: Add all areas to find the total area.** $$\text{Total Area} = 36 + 1 + 1.5 = 38.5$$ 7. **Final answer:** The area of the compound figure is **38.5 square yards**.