1. **State the problem:** Amy has an original image with dimensions width $= \frac{2}{3}$ ft and height $= \frac{1}{2}$ ft. She enlarges it so the new image has width 6 ft and length 8 ft. We need to find the unit rate of area of the enlarged image per square foot of the original image. 2. **Calculate the area of the original image:** $$\text{Area}_{original} = \frac{2}{3} \times \frac{1}{2} = \frac{2}{6} = \frac{1}{3} \text{ square feet}$$ 3. **Calculate the area of the enlarged image:** $$\text{Area}_{enlarged} = 6 \times 8 = 48 \text{ square feet}$$ 4. **Find the unit rate of area enlargement:** This is the ratio of the enlarged area to the original area: $$\frac{\text{Area}_{enlarged}}{\text{Area}_{original}} = \frac{48}{\frac{1}{3}}$$ 5. **Simplify the division:** $$\frac{48}{\frac{1}{3}} = 48 \times 3 = 144$$ 6. **Interpretation:** The enlarged image has 144 square feet per square foot of the original image. **Final answer:** 144 square feet per square foot (Option B).