1. **State the problem:** We need to find the area of an irregular polygon composed of rectangles and a square with given side lengths in millimeters. 2. **Break down the figure into simpler shapes:** The figure consists of: - A vertical rectangle on the left with height 11 mm and width 5 mm. - A square at the bottom with sides 5 mm. - A small rectangular protrusion on the top right with dimensions 3 mm by 2 mm. 3. **Calculate the area of each shape:** - Area of vertical rectangle: $$5 \times 11 = 55$$ mm² - Area of square: $$5 \times 5 = 25$$ mm² - Area of small rectangle: $$3 \times 2 = 6$$ mm² 4. **Sum the areas:** $$55 + 25 + 6 = 86$$ mm² 5. **Final answer:** The total area of the figure is **86 square millimeters**.