1. **Stating the problem:** We have two figures: Figur A is a rectangle with width $8 \cdot x$ cm and height $2 \cdot x$ cm. Figur B is an equilateral triangle with side length $7 \cdot x$ cm. 2. **Formulas and rules:** - Area of a rectangle: $$A = \text{width} \times \text{height}$$ - Area of an equilateral triangle: $$A = \frac{\sqrt{3}}{4} \times (\text{side})^2$$ 3. **Calculate the area of Figur A (rectangle):** $$A_A = (8 \cdot x) \times (2 \cdot x) = 16x^2$$ 4. **Calculate the area of Figur B (equilateral triangle):** $$A_B = \frac{\sqrt{3}}{4} \times (7 \cdot x)^2 = \frac{\sqrt{3}}{4} \times 49x^2 = \frac{49\sqrt{3}}{4} x^2$$ 5. **Summary:** - Area of rectangle: $$16x^2$$ - Area of equilateral triangle: $$\frac{49\sqrt{3}}{4} x^2$$ These expressions give the areas in terms of $x$ without measuring with a ruler.