1. **State the problem:** Find the area of the given irregular polygon with right angles. 2. **Understand the shape:** The figure looks like a large rectangle with a smaller rectangle cut out from the bottom middle. 3. **Identify dimensions:** - Large rectangle: width = 8 ft, height = 6 ft - Cut-out rectangle: width = 4 ft, height = 3 ft 4. **Formula for area of rectangle:** $$\text{Area} = \text{width} \times \text{height}$$ 5. **Calculate area of large rectangle:** $$8 \times 6 = 48 \text{ ft}^2$$ 6. **Calculate area of cut-out rectangle:** $$4 \times 3 = 12 \text{ ft}^2$$ 7. **Calculate area of the figure:** Subtract the cut-out area from the large rectangle area: $$48 - 12 = 36 \text{ ft}^2$$ **Final answer:** The area of the figure is **36 ft²**.