1. **State the problem:** Find the area of the irregular polygon composed of three simpler shapes: a vertical rectangle, a horizontal rectangle, and a trapezoid. 2. **Identify the shapes and their dimensions:** - Vertical rectangle: height = 21 m, width = 3 m - Horizontal rectangle: length = 24 m, height = 12 m - Trapezoid: height = 9 m, bases = 12 m (top) and 21 m (bottom) 3. **Formulas used:** - Area of rectangle = width \times height - Area of trapezoid = \frac{(base_1 + base_2)}{2} \times height 4. **Calculate each area:** - Vertical rectangle area = $3 \times 21 = 63$ m$^2$ - Horizontal rectangle area = $24 \times 12 = 288$ m$^2$ - Trapezoid area = $\frac{(12 + 21)}{2} \times 9$ 5. **Simplify trapezoid area:** $$ \frac{(12 + 21)}{2} \times 9 = \frac{33}{2} \times 9 $$ 6. **Calculate trapezoid area:** $$ \frac{33}{2} \times 9 = 33 \times \frac{9}{2} = 33 \times 4.5 = 148.5 $$ 7. **Add all areas to find total area:** $$ 63 + 288 + 148.5 = 499.5 $$ **Final answer:** The area of the figure is **499.5 m$^2$** to the nearest tenth.