1. **Problem:** Find the perimeter and area of a triangle with sides 30 cm, 14.7 cm, and 20 cm, and height 13 cm. 2. **Formulas:** - Perimeter $P = a + b + c$ - Area $A = \frac{1}{2} \times \text{base} \times \text{height}$ 3. **Calculations:** - Perimeter: $P = 30 + 14.7 + 20 = 64.7$ cm - Area: $A = \frac{1}{2} \times 30 \times 13 = 195$ cm$^2$ 4. **Problem:** Find the perimeter and area of a parallelogram with base 10.6 m, side 6.5 m, and height 5.8 m. 5. **Formulas:** - Perimeter $P = 2 \times (\text{base} + \text{side})$ - Area $A = \text{base} \times \text{height}$ 6. **Calculations:** - Perimeter: $P = 2 \times (10.6 + 6.5) = 2 \times 17.1 = 34.2$ m - Area: $A = 10.6 \times 5.8 = 61.48$ m$^2$ 7. **Problem:** Find the perimeter and area of a trapezoid with bases 42 ft and 14 ft, height 18 ft, and sides 30 ft and 20 ft. 8. **Formulas:** - Perimeter $P = a + b + c + d$ - Area $A = \frac{1}{2} \times (\text{base}_1 + \text{base}_2) \times \text{height}$ 9. **Calculations:** - Perimeter: $P = 42 + 14 + 30 + 20 = 106$ ft - Area: $A = \frac{1}{2} \times (42 + 14) \times 18 = \frac{1}{2} \times 56 \times 18 = 504$ ft$^2$ 10. **Problem:** Pete walked around a park three times. The park is a trapezoid with sides 1 mi, 1.6 mi, 2 mi, and 2.3 mi. 11. **Formulas:** - Perimeter of park $P = 1 + 1.6 + 2 + 2.3 = 6.9$ mi - Total distance walked $= 3 \times P = 3 \times 6.9 = 20.7$ mi 12. **Problem:** Find the cost of sod for a football field parallelogram with base 120 yd and height 53 1/3 yd. 13. **Formulas:** - Area $A = \text{base} \times \text{height} = 120 \times 53\frac{1}{3} = 120 \times \frac{160}{3} = 6400$ yd$^2$ - Cost $= 6400 \times 1.35 = 8640$ **Final answers:** 1. Triangle: Perimeter = 64.7 cm, Area = 195 cm$^2$ 2. Parallelogram: Perimeter = 34.2 m, Area = 61.48 m$^2$ 3. Trapezoid: Perimeter = 106 ft, Area = 504 ft$^2$ 4. Park walk distance = 20.7 mi 5. Sod cost = 8640